Release date lottery
Re: Release date lottery
I have a friend. He is Condor pilot since 2006. Tomorrow he selebrates his 70th-year anniversary. I hoped that I will buy him Condor v.2 as a birthday gift but....
Last edited by Someone on Sat Jan 13, 2018 6:59 pm, edited 1 time in total.
Re: Release date lottery
IMVHO 10 months...
Notice - it will be after RL season - perfect time to release C2.
In lottery I bet for September. Little mistake.
Notice - it will be after RL season - perfect time to release C2.
In lottery I bet for September. Little mistake.
- flying.islander
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Re: Release date lottery
I think you're the winner! You're the first person to post this date without editing their previous post.orion1210 wrote:23JAN18??
CN: TXS
TX-ScubaSteve
TX-ScubaSteve
Re: Release date lottery
I’m not sure if the rules stipulated anything regarding post editing... fingers crossed for the 23rd either way, but it did say only one guess per person.
It would be the first time I’ve won anything in condor... and probably the last!
It would be the first time I’ve won anything in condor... and probably the last!
Re: Release date lottery
01/04/2018
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Re: Release date lottery
It will be the 23.01.2018, when you look at the FBPage i think you can see it
Condor-Club:
Reg: PCR
D-2859
Name: P. Riessner
Reg: PCR
D-2859
Name: P. Riessner
Re: Release date lottery
Well here we finally know the date now
Let me explain:
* Number 8 posted on Facebook on January 16th
* Number 7 posted on Facebook on January 18th
The numbers posted are a countdown of the remaining days.
And since there are 31 days in January, the logical continuation gives us:
Un + 1 = f (Un)
Un = x mod (1+ (n + 1) * y)
...
Good simply:
January 16th + (2 * 8 days) = 32
31 days in January, so the exact date of release will probably be:
☆☆☆☆ February 1, 2018 ☆☆☆☆
Let me explain:
* Number 8 posted on Facebook on January 16th
* Number 7 posted on Facebook on January 18th
The numbers posted are a countdown of the remaining days.
And since there are 31 days in January, the logical continuation gives us:
Un + 1 = f (Un)
Un = x mod (1+ (n + 1) * y)
...
Good simply:
January 16th + (2 * 8 days) = 32
31 days in January, so the exact date of release will probably be:
☆☆☆☆ February 1, 2018 ☆☆☆☆
Re: Release date lottery
It's like a climate model.. too many assumptions.zou wrote:Well here we finally know the date now
Let me explain:
* Number 8 posted on Facebook on January 16th
* Number 7 posted on Facebook on January 18th
The numbers posted are a countdown of the remaining days.
And since there are 31 days in January, the logical continuation gives us:
Un + 1 = f (Un)
Un = x mod (1+ (n + 1) * y)
...
Good simply:
January 16th + (2 * 8 days) = 32
31 days in January, so the exact date of release will probably be:
☆☆☆☆ February 1, 2018 ☆☆☆☆
Chris Wedgwood,
Condor Team
Condor Team
Re: Release date lottery
How can something be exact and probably lolGood simply:
January 16th + (2 * 8 days) = 32
31 days in January, so the exact date of release will probably be:
☆☆☆☆ February 1, 2018 ☆☆☆☆